Routing problems¶
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Given \(n\) cities and the distance \(d_{ij}\) between every ordered pair, a solution is a tour that visits every city exactly once and returns to the first one.
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The objective is to minimize the total length of the tour; the members differ in the properties of the distances, symmetric, metric or asymmetric.
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The Hamiltonian cycle problem is the decision problem on a graph: it asks whether a tour made of edges of the graph exists.
| Problem | Acronym | Difference |
|---|---|---|
| Travelling salesman problem | TSP | The central problem of the family. |
| Metric travelling salesman problem | metric TSP | The special case of the TSP with the triangle inequality, where approximation guarantees exist. |
| Asymmetric travelling salesman problem | ATSP | The TSP is the special case of the ATSP in which \(d_{ij}=d_{ji}\) for all \(i,j\); an ATSP instance has \((n-1)!\) tours. |
| Hamiltonian cycle problem | HCP | With \(d_{ij}=1\) on the edges and a large distance elsewhere, \(G\) is Hamiltonian if and only if \(z(I_G)=n\): the TSP contains it. |